Run a bat file with argument via server method

RE: Run a bat file with argument via server method

Gopikrishnan — Wed, 20 May 2020 16:08:46 GMT

Glad to hear. Stay safe..

RE: Run a bat file with argument via server method

DucTran — Wed, 20 May 2020 08:18:54 GMT

I Tried run server method with your Hello.bat, It's worked fine.

The problem is the my bat file :) . Thanks for your support!

RE: Run a bat file with argument via server method

Gopikrishnan — Tue, 19 May 2020 17:20:19 GMT

Hi DucTran

Hope you have modified the directory, bat file name in above method. If it is executed, might be the bat file executed correctly. Can you confirm what is there in the bat file. If you want to test whether the method is working or not, you can keep below lines in bat file and run

Open Notepad

Copy below line and save as Hello.bat

@echo off
@echo Testing Bat File Operation from ARAS Innovator> output.txt

Copy this bat file to the input directory as per the method

Execute the method

Verify the directory provided in the method for output

RE: Run a bat file with argument via server method

DucTran — Tue, 19 May 2020 07:30:04 GMT

I have tried your code, it's go to the end of line (return this;) fine without exception. but bat file is not execute, the output.txt is not created.

I am sure the folder of bat file on server is shared for everyone.

RE: Run a bat file with argument via server method

Gopikrishnan — Tue, 19 May 2020 06:11:14 GMT

Hi DucTran

You can use below server method to run the bat file

string inputPath = string.Format(@"C:\Backup\Test"); //Directory of the Bat file
System.Diagnostics.Process command = new System.Diagnostics.Process();
command.StartInfo.FileName = Path.Combine(inputPath, "Hello.bat"); // Bat file Name
string outputPath = Path.Combine(inputPath, "output.txt"); //Output file
command.StartInfo.Arguments = string.Format("\"{0}\" \"{1}\" \"{2}\"", inputPath, outputPath, inputPath);
command.StartInfo.UseShellExecute = false;
command.StartInfo.CreateNoWindow = true;
command.StartInfo.WorkingDirectory = inputPath;
command.Start();
if (!command.WaitForExit(3000)) //Execution allowed time to prevent system hung
{
throw new Exception(string.Format("The process '{0}' is not responding", command.StartInfo.FileName));
}

if (command.ExitCode != 0)
{
throw new Exception(string.Format("The process '{0}' has finished with error (ErrorCode={1})", command.StartInfo.FileName, command.ExitCode));
}
return this;

Note: If you get access denied error, provide access to that folder to everyone an try

Thank You

Gopikrishnan R